#18199: "Swiss tournament pairing improvement: color selection (hive, chess)"
Kaj se je zgodilo? Prosimo, izberi spodaj
Kaj se je zgodilo? Prosimo, izberi spodaj
Prosimo preverite ali že obstaja poročilo o isti zadevi
Če je tako, GLASUJTE za to poročilo. Poročila z največ glasovi se obravnavajo PREDNOSTNO!
# | Status | Votes | Game | Type | Title | Last update |
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Natančen opis
• Kopirajte / prilepite sporočilo o napaki, ki ga vidite na zaslonu, če ga imate.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Prosim, pojasnite, kaj ste hoteli storiti, kaj ste naredili in kaj se je zgodilo
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Kopirajte / prilepite besedilo, prikazano v angleščini, namesto v vašem jeziku. Če imate sliko zaslona te napake (dobra praksa), lahko uporabite Imgur.com za nalaganje in kopirate/prilepite povezavo do slike tukaj.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Je ta tekst dosegljiv v prevajalnem sistemu? Če ja, ali je bil preveden več kot 24 ur nazaj?
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Natančno in jedrnato pojasnite svoj predlog, da bo čim lažje razumeti, kaj mislite.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Kaj je bilo prikazano na zaslonu, ko ste bili blokirani (prazen zaslon? Del vmesnika za igro? Sporočilo o napaki?)
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Kateri del pravil ni bil upoštevan pri priredbi za BGA
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Je kršitev pravil vidna na seznamu potez? Če je, pri kateri številki poteze?
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Katero potezo ste želeli narediti v igri?
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Kaj ste poskušali narediti, da bi izvedli to potezo v igri?
• Kaj se je zgodilo, ko ste poskusili to storiti (sporočilo o napaki, sporočilo v vrstici stanja, ...)?
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Na kateri točki v igri se je težava pojavila (katera navodila so bila prikazana)
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Kaj se je zgodilo, ko ste poskušali narediti to potezo v igri (sporočilo o napaki, sporočilo v vrstici stanja, ...)?
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Prosim opiši problem s prikazom. Če imate sliko zaslona te napake (dobra praksa), lahko uporabite Imgur.com za nalaganje in kopirate/prilepite povezavo do slike tukaj.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Kopirajte / prilepite besedilo, prikazano v angleščini, namesto v vašem jeziku. Če imate sliko zaslona te napake (dobra praksa), lahko uporabite Imgur.com za nalaganje in kopirate/prilepite povezavo do slike tukaj.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Je ta tekst dosegljiv v prevajalnem sistemu? Če ja, ali je bil preveden več kot 24 ur nazaj?
• Kateri brskalnik uporabljaš?
Google Chrome v81
• Natančno in jedrnato pojasnite svoj predlog, da bo čim lažje razumeti, kaj mislite.
This improvement request is for games like hive and chess where the player can be either white or black (or other two colors). Currently, the color for the individual rounds of the tournament is selected 100% randomly which is far from ideal. In Hive it is quite important who plays with white because on a certain level it is considered as a big advantage. Therefore, it should be prevented by the BGA pairing system that someone plays most of his/her games with the same color.
The pairing system in Swiss tournaments should be improved according to the standard Swiss-tournament rules, described for example here: en.wikipedia.org/wiki/Swiss-system_tournament
Main point (cited from wiki): "In chess, the pairing rules try to ensure that each player plays an equal number of games with white and black, alternate colors in each round being the most preferable, and a particular effort is made to not assign a player the same color three times consecutively."
For example: For the first round random colors are selected. Let's say that I play with white. In the second round, I should play with black. In the third round again with white, and so on.
However, the color is not the main criteria based on which the pairing should work. The number of points is the main criteria (it already works like this). Therefore, it can occur that there are only two players with the same number of points who haven't played against each other yet AND both of them played with the same color in the previous round. In this case it is allowed to play with the same color in 2 consecutive rounds.
Similar conflict: there are 4 people with the same number of points and 3 of them played with white in the previous round. Solution: again, it is allowed in this case to select the same color for the next round for one of those 3 people.
Recommendation: It would be the best if the BGA swiss pairing system would follow most of the general rules which are defined by the Internation Chess Federation (FIDE): handbook.fide.com/chapter/C0401
Please, could you implement this improvement for the Hive community? :)
• Kateri brskalnik uporabljaš?
Google Chrome v81
Zgodovina poročil
boardgamearena.com/tournament?id=38119
For example, in this tournament Frasco has all 4 games as white and pcapella has all 4 games black boardgamearena.com/tournament?id=106569
boardgamearena.com/bug?id=32483
boardgamearena.com/bug?id=32713
boardgamearena.com/bug?id=72619
Dodaj nekaj k temu poročilu
- Drug ID mize/ premikanje ID-ja
- Ali je F5 rešil težavo?
- Se je problem pojavil večkrat? Vsakič? Naključno?
- Če imate sliko zaslona te napake (dobra praksa), lahko uporabite Imgur.com za nalaganje in kopirate/prilepite povezavo do slike tukaj.